X^2+2x+8=4x

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Solution for X^2+2x+8=4x equation:



X^2+2X+8=4X
We move all terms to the left:
X^2+2X+8-(4X)=0
We add all the numbers together, and all the variables
X^2-2X+8=0
a = 1; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·1·8
Δ = -28
Delta is less than zero, so there is no solution for the equation

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